2(2y-4)-2(6y+1)=-26

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Solution for 2(2y-4)-2(6y+1)=-26 equation: 



2(2y-4)-2(6y+1)=-26

We move all terms to the left:

2(2y-4)-2(6y+1)-(-26)=0

We add all the numbers together, and all the variables

2(2y-4)-2(6y+1)+26=0

We multiply parentheses

4y-12y-8-2+26=0

We add all the numbers together, and all the variables

-8y+16=0

We move all terms containing y to the left, all other terms to the right

-8y=-16

y=-16/-8

y=+2

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