2(2y-5)+15=12

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Solution for 2(2y-5)+15=12 equation: 



2(2y-5)+15=12

We move all terms to the left:

2(2y-5)+15-(12)=0

We add all the numbers together, and all the variables

2(2y-5)+3=0

We multiply parentheses

4y-10+3=0

We add all the numbers together, and all the variables

4y-7=0

We move all terms containing y to the left, all other terms to the right

4y=7

y=7/4

y=1+3/4

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