2(2y-5)/3=(5)(x+y)/2

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Solution for 2(2y-5)/3=(5)(x+y)/2 equation: 


x in (-oo:+oo)

(2*(2*y-5))/3 = (5*(x+y))/2 // - (5*(x+y))/2

(2*(2*y-5))/3-((5*(x+y))/2) = 0

(2*(2*y-5))/3+(-5/2)*(x+y) = 0

(2*(2*y-5))/3-5/2*(x+y) = 0

(2*(2*y-5))/3+(-5/2*3*(x+y))/3 = 0

2*(2*y-5)-5/2*3*(x+y) = 0

-15/2*x-7/2*y-10 = 0

(-15/2*x-7/2*y-10)/3 = 0

(-15/2*x-7/2*y-10)/3 = 0 // * 3

-15/2*x-7/2*y-10 = 0

-15/2*x-7/2*y-10 = 0 // + -7/2*y-10

-15/2*x = -(-7/2*y-10) // : -15/2

x = (-(-7/2*y-10))/(-15/2)

x = -2/15*(10-(-7/2*y))

x = -2/15*(10-(-7/2*y))

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