2(2y-5)=3(5-2y)

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Solution for 2(2y-5)=3(5-2y) equation: 



2(2y-5)=3(5-2y)

We move all terms to the left:

2(2y-5)-(3(5-2y))=0

We add all the numbers together, and all the variables

2(2y-5)-(3(-2y+5))=0

We multiply parentheses

4y-(3(-2y+5))-10=0



We calculate terms in parentheses: -(3(-2y+5)), so:

3(-2y+5)

We multiply parentheses

-6y+15

Back to the equation:

-(-6y+15)



We get rid of parentheses

4y+6y-15-10=0

We add all the numbers together, and all the variables

10y-25=0

We move all terms containing y to the left, all other terms to the right

10y=25

y=25/10

y=2+1/2

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