2(2z+1)=3(z-2)

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Solution for 2(2z+1)=3(z-2) equation: 



2(2z+1)=3(z-2)

We move all terms to the left:

2(2z+1)-(3(z-2))=0

We multiply parentheses

4z-(3(z-2))+2=0



We calculate terms in parentheses: -(3(z-2)), so:

3(z-2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We get rid of parentheses

4z-3z+6+2=0

We add all the numbers together, and all the variables

z+8=0

We move all terms containing z to the left, all other terms to the right

z=-8

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