2(2z+2)=4(z-1)+7

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Solution for 2(2z+2)=4(z-1)+7 equation: 


Simplifying
2(2z + 2) = 4(z + -1) + 7

Reorder the terms:
2(2 + 2z) = 4(z + -1) + 7
(2 * 2 + 2z * 2) = 4(z + -1) + 7
(4 + 4z) = 4(z + -1) + 7

Reorder the terms:
4 + 4z = 4(-1 + z) + 7
4 + 4z = (-1 * 4 + z * 4) + 7
4 + 4z = (-4 + 4z) + 7

Reorder the terms:
4 + 4z = -4 + 7 + 4z

Combine like terms: -4 + 7 = 3
4 + 4z = 3 + 4z

Add '-4z' to each side of the equation.
4 + 4z + -4z = 3 + 4z + -4z

Combine like terms: 4z + -4z = 0
4 + 0 = 3 + 4z + -4z
4 = 3 + 4z + -4z

Combine like terms: 4z + -4z = 0
4 = 3 + 0
4 = 3

Solving
4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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