2(2z+5)=3(5z-4)

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Solution for 2(2z+5)=3(5z-4) equation: 



2(2z+5)=3(5z-4)

We move all terms to the left:

2(2z+5)-(3(5z-4))=0

We multiply parentheses

4z-(3(5z-4))+10=0



We calculate terms in parentheses: -(3(5z-4)), so:

3(5z-4)

We multiply parentheses

15z-12

Back to the equation:

-(15z-12)



We get rid of parentheses

4z-15z+12+10=0

We add all the numbers together, and all the variables

-11z+22=0

We move all terms containing z to the left, all other terms to the right

-11z=-22

z=-22/-11

z=+2

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