2(2z+7)=1/2(6z-12)-2

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Solution for 2(2z+7)=1/2(6z-12)-2 equation:



2(2z+7)=1/2(6z-12)-2
We move all terms to the left:
2(2z+7)-(1/2(6z-12)-2)=0
Domain of the equation: 2(6z-12)-2)!=0
z∈R
We multiply parentheses
4z-(1/2(6z-12)-2)+14=0
We multiply all the terms by the denominator
4z*2(6z-12)+14*2(6z-12)-2)-(1-2)=0
We add all the numbers together, and all the variables
4z*2(6z-12)+14*2(6z-12)-2)-(-1)=0
We add all the numbers together, and all the variables
4z*2(6z-12)+14*2(6z-12)=0
Wy multiply elements
8z^2(6+28z(6=0

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