2(2z-2)=3(z+4)

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Solution for 2(2z-2)=3(z+4) equation:


Simplifying
2(2z + -2) = 3(z + 4)

Reorder the terms:
2(-2 + 2z) = 3(z + 4)
(-2 * 2 + 2z * 2) = 3(z + 4)
(-4 + 4z) = 3(z + 4)

Reorder the terms:
-4 + 4z = 3(4 + z)
-4 + 4z = (4 * 3 + z * 3)
-4 + 4z = (12 + 3z)

Solving
-4 + 4z = 12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-4 + 4z + -3z = 12 + 3z + -3z

Combine like terms: 4z + -3z = 1z
-4 + 1z = 12 + 3z + -3z

Combine like terms: 3z + -3z = 0
-4 + 1z = 12 + 0
-4 + 1z = 12

Add '4' to each side of the equation.
-4 + 4 + 1z = 12 + 4

Combine like terms: -4 + 4 = 0
0 + 1z = 12 + 4
1z = 12 + 4

Combine like terms: 12 + 4 = 16
1z = 16

Divide each side by '1'.
z = 16

Simplifying
z = 16

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