2(2z-3)=3(z+4)

Solution for 2(2z-3)=3(z+4) equation:

Simplifying
2(2z + -3) = 3(z + 4)

Reorder the terms:
2(-3 + 2z) = 3(z + 4)
(-3 * 2 + 2z * 2) = 3(z + 4)
(-6 + 4z) = 3(z + 4)

Reorder the terms:
-6 + 4z = 3(4 + z)
-6 + 4z = (4 * 3 + z * 3)
-6 + 4z = (12 + 3z)

Solving
-6 + 4z = 12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-6 + 4z + -3z = 12 + 3z + -3z

Combine like terms: 4z + -3z = 1z
-6 + 1z = 12 + 3z + -3z

Combine like terms: 3z + -3z = 0
-6 + 1z = 12 + 0
-6 + 1z = 12

Add '6' to each side of the equation.
-6 + 6 + 1z = 12 + 6

Combine like terms: -6 + 6 = 0
0 + 1z = 12 + 6
1z = 12 + 6

Combine like terms: 12 + 6 = 18
1z = 18

Divide each side by '1'.
z = 18

Simplifying
z = 18