2(2z-4)=3(z-2)

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Solution for 2(2z-4)=3(z-2) equation:


Simplifying
2(2z + -4) = 3(z + -2)

Reorder the terms:
2(-4 + 2z) = 3(z + -2)
(-4 * 2 + 2z * 2) = 3(z + -2)
(-8 + 4z) = 3(z + -2)

Reorder the terms:
-8 + 4z = 3(-2 + z)
-8 + 4z = (-2 * 3 + z * 3)
-8 + 4z = (-6 + 3z)

Solving
-8 + 4z = -6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-8 + 4z + -3z = -6 + 3z + -3z

Combine like terms: 4z + -3z = 1z
-8 + 1z = -6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-8 + 1z = -6 + 0
-8 + 1z = -6

Add '8' to each side of the equation.
-8 + 8 + 1z = -6 + 8

Combine like terms: -8 + 8 = 0
0 + 1z = -6 + 8
1z = -6 + 8

Combine like terms: -6 + 8 = 2
1z = 2

Divide each side by '1'.
z = 2

Simplifying
z = 2

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