2(2z-4)=4(z+3)

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Solution for 2(2z-4)=4(z+3) equation:


Simplifying
2(2z + -4) = 4(z + 3)

Reorder the terms:
2(-4 + 2z) = 4(z + 3)
(-4 * 2 + 2z * 2) = 4(z + 3)
(-8 + 4z) = 4(z + 3)

Reorder the terms:
-8 + 4z = 4(3 + z)
-8 + 4z = (3 * 4 + z * 4)
-8 + 4z = (12 + 4z)

Add '-4z' to each side of the equation.
-8 + 4z + -4z = 12 + 4z + -4z

Combine like terms: 4z + -4z = 0
-8 + 0 = 12 + 4z + -4z
-8 = 12 + 4z + -4z

Combine like terms: 4z + -4z = 0
-8 = 12 + 0
-8 = 12

Solving
-8 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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