2(2z-5)=3(z+5)+z

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Solution for 2(2z-5)=3(z+5)+z equation: 


Simplifying
2(2z + -5) = 3(z + 5) + z

Reorder the terms:
2(-5 + 2z) = 3(z + 5) + z
(-5 * 2 + 2z * 2) = 3(z + 5) + z
(-10 + 4z) = 3(z + 5) + z

Reorder the terms:
-10 + 4z = 3(5 + z) + z
-10 + 4z = (5 * 3 + z * 3) + z
-10 + 4z = (15 + 3z) + z

Combine like terms: 3z + z = 4z
-10 + 4z = 15 + 4z

Add '-4z' to each side of the equation.
-10 + 4z + -4z = 15 + 4z + -4z

Combine like terms: 4z + -4z = 0
-10 + 0 = 15 + 4z + -4z
-10 = 15 + 4z + -4z

Combine like terms: 4z + -4z = 0
-10 = 15 + 0
-10 = 15

Solving
-10 = 15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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