2(2z-5)=7(z+2)

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Solution for 2(2z-5)=7(z+2) equation:


Simplifying
2(2z + -5) = 7(z + 2)

Reorder the terms:
2(-5 + 2z) = 7(z + 2)
(-5 * 2 + 2z * 2) = 7(z + 2)
(-10 + 4z) = 7(z + 2)

Reorder the terms:
-10 + 4z = 7(2 + z)
-10 + 4z = (2 * 7 + z * 7)
-10 + 4z = (14 + 7z)

Solving
-10 + 4z = 14 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-10 + 4z + -7z = 14 + 7z + -7z

Combine like terms: 4z + -7z = -3z
-10 + -3z = 14 + 7z + -7z

Combine like terms: 7z + -7z = 0
-10 + -3z = 14 + 0
-10 + -3z = 14

Add '10' to each side of the equation.
-10 + 10 + -3z = 14 + 10

Combine like terms: -10 + 10 = 0
0 + -3z = 14 + 10
-3z = 14 + 10

Combine like terms: 14 + 10 = 24
-3z = 24

Divide each side by '-3'.
z = -8

Simplifying
z = -8

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