2(2z-6)=28

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Solution for 2(2z-6)=28 equation: 



2(2z-6)=28

We move all terms to the left:

2(2z-6)-(28)=0

We multiply parentheses

4z-12-28=0

We add all the numbers together, and all the variables

4z-40=0

We move all terms containing z to the left, all other terms to the right

4z=40

z=40/4

z=10

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