2(2z/3)=3(z+2)

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Solution for 2(2z/3)=3(z+2) equation: 



2(2z/3)=3(z+2)

We move all terms to the left:

2(2z/3)-(3(z+2))=0

We add all the numbers together, and all the variables

2(+2z/3)-(3(z+2))=0

We multiply parentheses

4z-(3(z+2))=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

4z-3z-6=0

We add all the numbers together, and all the variables

z-6=0

We move all terms containing z to the left, all other terms to the right

z=6

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