2(3+19r)=18

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Solution for 2(3+19r)=18 equation: 



2(3+19r)=18

We move all terms to the left:

2(3+19r)-(18)=0

We add all the numbers together, and all the variables

2(19r+3)-18=0

We multiply parentheses

38r+6-18=0

We add all the numbers together, and all the variables

38r-12=0

We move all terms containing r to the left, all other terms to the right

38r=12

r=12/38

r=6/19

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