2(3+2b+b)=66

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Solution for 2(3+2b+b)=66 equation: 



2(3+2b+b)=66

We move all terms to the left:

2(3+2b+b)-(66)=0

We add all the numbers together, and all the variables

2(3b+3)-66=0

We multiply parentheses

6b+6-66=0

We add all the numbers together, and all the variables

6b-60=0

We move all terms containing b to the left, all other terms to the right

6b=60

b=60/6

b=10

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