2(3+3y)+2=20

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Solution for 2(3+3y)+2=20 equation: 



2(3+3y)+2=20

We move all terms to the left:

2(3+3y)+2-(20)=0

We add all the numbers together, and all the variables

2(3y+3)+2-20=0

We add all the numbers together, and all the variables

2(3y+3)-18=0

We multiply parentheses

6y+6-18=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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