2(3+4b)-2=-5(1-b)+3

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Solution for 2(3+4b)-2=-5(1-b)+3 equation: 



2(3+4b)-2=-5(1-b)+3

We move all terms to the left:

2(3+4b)-2-(-5(1-b)+3)=0

We add all the numbers together, and all the variables

2(4b+3)-(-5(-1b+1)+3)-2=0

We multiply parentheses

8b-(-5(-1b+1)+3)+6-2=0



We calculate terms in parentheses: -(-5(-1b+1)+3), so:

-5(-1b+1)+3

We multiply parentheses

5b-5+3

We add all the numbers together, and all the variables

5b-2

Back to the equation:

-(5b-2)



We add all the numbers together, and all the variables

8b-(5b-2)+4=0

We get rid of parentheses

8b-5b+2+4=0

We add all the numbers together, and all the variables

3b+6=0

We move all terms containing b to the left, all other terms to the right

3b=-6

b=-6/3

b=-2

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