2(3+4m)=-6=48

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Solution for 2(3+4m)=-6=48 equation: 



2(3+4m)=-6=48

We move all terms to the left:

2(3+4m)-(-6)=0

We add all the numbers together, and all the variables

2(4m+3)-(-6)=0

We add all the numbers together, and all the variables

2(4m+3)+6=0

We multiply parentheses

8m+6+6=0

We add all the numbers together, and all the variables

8m+12=0

We move all terms containing m to the left, all other terms to the right

8m=-12

m=-12/8

m=-1+1/2

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