2(3+9z)=3(-10+10z)

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Solution for 2(3+9z)=3(-10+10z) equation: 



2(3+9z)=3(-10+10z)

We move all terms to the left:

2(3+9z)-(3(-10+10z))=0

We add all the numbers together, and all the variables

2(9z+3)-(3(10z-10))=0

We multiply parentheses

18z-(3(10z-10))+6=0



We calculate terms in parentheses: -(3(10z-10)), so:

3(10z-10)

We multiply parentheses

30z-30

Back to the equation:

-(30z-30)



We get rid of parentheses

18z-30z+30+6=0

We add all the numbers together, and all the variables

-12z+36=0

We move all terms containing z to the left, all other terms to the right

-12z=-36

z=-36/-12

z=+3

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