2(3+g)-g=-4(g+1)

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Solution for 2(3+g)-g=-4(g+1) equation:



2(3+g)-g=-4(g+1)
We move all terms to the left:
2(3+g)-g-(-4(g+1))=0
We add all the numbers together, and all the variables
2(g+3)-g-(-4(g+1))=0
We add all the numbers together, and all the variables
-1g+2(g+3)-(-4(g+1))=0
We multiply parentheses
-1g+2g-(-4(g+1))+6=0
We calculate terms in parentheses: -(-4(g+1)), so:
-4(g+1)
We multiply parentheses
-4g-4
Back to the equation:
-(-4g-4)
We add all the numbers together, and all the variables
g-(-4g-4)+6=0
We get rid of parentheses
g+4g+4+6=0
We add all the numbers together, and all the variables
5g+10=0
We move all terms containing g to the left, all other terms to the right
5g=-10
g=-10/5
g=-2

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