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2(3+x)-10=4(2-x)
We move all terms to the left:
2(3+x)-10-(4(2-x))=0
We add all the numbers together, and all the variables
2(x+3)-(4(-1x+2))-10=0
We multiply parentheses
2x-(4(-1x+2))+6-10=0
We calculate terms in parentheses: -(4(-1x+2)), so:We add all the numbers together, and all the variables
4(-1x+2)
We multiply parentheses
-4x+8
Back to the equation:
-(-4x+8)
2x-(-4x+8)-4=0
We get rid of parentheses
2x+4x-8-4=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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