2(3+x)=3(x+1)

Solution for 2(3+x)=3(x+1) equation:

2(3+x)=3(x+1)

We move all terms to the left:

2(3+x)-(3(x+1))=0

We add all the numbers together, and all the variables

2(x+3)-(3(x+1))=0

We multiply parentheses

2x-(3(x+1))+6=0


We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)


We get rid of parentheses

2x-3x-3+6=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3