2(3+x)=3(x+1)

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Solution for 2(3+x)=3(x+1) equation:



2(3+x)=3(x+1)
We move all terms to the left:
2(3+x)-(3(x+1))=0
We add all the numbers together, and all the variables
2(x+3)-(3(x+1))=0
We multiply parentheses
2x-(3(x+1))+6=0
We calculate terms in parentheses: -(3(x+1)), so:
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
We get rid of parentheses
2x-3x-3+6=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3

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