2(3+y)=2(2y-1)+6

Solution for 2(3+y)=2(2y-1)+6 equation:

2(3+y)=2(2y-1)+6

We move all terms to the left:

2(3+y)-(2(2y-1)+6)=0

We add all the numbers together, and all the variables

2(y+3)-(2(2y-1)+6)=0

We multiply parentheses

2y-(2(2y-1)+6)+6=0


We calculate terms in parentheses: -(2(2y-1)+6), so:

2(2y-1)+6

We multiply parentheses

4y-2+6

We add all the numbers together, and all the variables

4y+4

Back to the equation:

-(4y+4)


We get rid of parentheses

2y-4y-4+6=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1