2(3-)-2b=6(-b+2)-26

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Solution for 2(3-)-2b=6(-b+2)-26 equation: 



2(3-)-2b=6(-b+2)-26

We move all terms to the left:

2(3-)-2b-(6(-b+2)-26)=0

We add all the numbers together, and all the variables

-2b-(6(-1b+2)-26)+20=0



We calculate terms in parentheses: -(6(-1b+2)-26), so:

6(-1b+2)-26

We multiply parentheses

-6b+12-26

We add all the numbers together, and all the variables

-6b-14

Back to the equation:

-(-6b-14)



We get rid of parentheses

-2b+6b+14+20=0

We add all the numbers together, and all the variables

4b+34=0

We move all terms containing b to the left, all other terms to the right

4b=-34

b=-34/4

b=-8+1/2

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