2(3-10h)=1/3(18-60h)

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Solution for 2(3-10h)=1/3(18-60h) equation: 



2(3-10h)=1/3(18-60h)

We move all terms to the left:

2(3-10h)-(1/3(18-60h))=0



Domain of the equation: 3(18-60h))!=0

h∈R



We add all the numbers together, and all the variables

2(-10h+3)-(1/3(-60h+18))=0

We multiply parentheses

-20h-(1/3(-60h+18))+6=0

We multiply all the terms by the denominator


-20h*3(-60h+18))-(1+6*3(-60h+18))=0

Wy multiply elements

-60h^2(-+18h(-=0

We use the square of the difference formula

-60h^2(-18h(-=0

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