2(3-2(z+4))=3(4-z)

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Solution for 2(3-2(z+4))=3(4-z) equation:


Simplifying
2(3 + -2(z + 4)) = 3(4 + -1z)

Reorder the terms:
2(3 + -2(4 + z)) = 3(4 + -1z)
2(3 + (4 * -2 + z * -2)) = 3(4 + -1z)
2(3 + (-8 + -2z)) = 3(4 + -1z)

Combine like terms: 3 + -8 = -5
2(-5 + -2z) = 3(4 + -1z)
(-5 * 2 + -2z * 2) = 3(4 + -1z)
(-10 + -4z) = 3(4 + -1z)
-10 + -4z = (4 * 3 + -1z * 3)
-10 + -4z = (12 + -3z)

Solving
-10 + -4z = 12 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
-10 + -4z + 3z = 12 + -3z + 3z

Combine like terms: -4z + 3z = -1z
-10 + -1z = 12 + -3z + 3z

Combine like terms: -3z + 3z = 0
-10 + -1z = 12 + 0
-10 + -1z = 12

Add '10' to each side of the equation.
-10 + 10 + -1z = 12 + 10

Combine like terms: -10 + 10 = 0
0 + -1z = 12 + 10
-1z = 12 + 10

Combine like terms: 12 + 10 = 22
-1z = 22

Divide each side by '-1'.
z = -22

Simplifying
z = -22

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