2(3-2)-5=3-(2+x)

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Solution for 2(3-2)-5=3-(2+x) equation: 



2(3-2)-5=3-(2+x)

We move all terms to the left:

2(3-2)-5-(3-(2+x))=0

We add all the numbers together, and all the variables

-(3-(x+2))-5+21=0

We add all the numbers together, and all the variables

-(3-(x+2))+16=0



We calculate terms in parentheses: -(3-(x+2)), so:

3-(x+2)

determiningTheFunctionDomain
-(x+2)+3

We get rid of parentheses

-x-2+3

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We get rid of parentheses

1x-1+16=0

We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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