2(3-2)-5=3-(2+x)

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Solution for 2(3-2)-5=3-(2+x) equation:



2(3-2)-5=3-(2+x)
We move all terms to the left:
2(3-2)-5-(3-(2+x))=0
We add all the numbers together, and all the variables
-(3-(x+2))-5+21=0
We add all the numbers together, and all the variables
-(3-(x+2))+16=0
We calculate terms in parentheses: -(3-(x+2)), so:
3-(x+2)
determiningTheFunctionDomain -(x+2)+3
We get rid of parentheses
-x-2+3
We add all the numbers together, and all the variables
-1x+1
Back to the equation:
-(-1x+1)
We get rid of parentheses
1x-1+16=0
We add all the numbers together, and all the variables
x+15=0
We move all terms containing x to the left, all other terms to the right
x=-15

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