2(3-2)=6z-1

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Solution for 2(3-2)=6z-1 equation: 



2(3-2)=6z-1

We move all terms to the left:

2(3-2)-(6z-1)=0

We add all the numbers together, and all the variables

-(6z-1)+21=0

We get rid of parentheses

-6z+1+21=0

We add all the numbers together, and all the variables

-6z+22=0

We move all terms containing z to the left, all other terms to the right

-6z=-22

z=-22/-6

z=3+2/3

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