2(3-2m)=5(2-m)

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Solution for 2(3-2m)=5(2-m) equation: 



2(3-2m)=5(2-m)

We move all terms to the left:

2(3-2m)-(5(2-m))=0

We add all the numbers together, and all the variables

2(-2m+3)-(5(-1m+2))=0

We multiply parentheses

-4m-(5(-1m+2))+6=0



We calculate terms in parentheses: -(5(-1m+2)), so:

5(-1m+2)

We multiply parentheses

-5m+10

Back to the equation:

-(-5m+10)



We get rid of parentheses

-4m+5m-10+6=0

We add all the numbers together, and all the variables

m-4=0

We move all terms containing m to the left, all other terms to the right

m=4

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