2(3-2m)=5(2-m)

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Solution for 2(3-2m)=5(2-m) equation:



2(3-2m)=5(2-m)
We move all terms to the left:
2(3-2m)-(5(2-m))=0
We add all the numbers together, and all the variables
2(-2m+3)-(5(-1m+2))=0
We multiply parentheses
-4m-(5(-1m+2))+6=0
We calculate terms in parentheses: -(5(-1m+2)), so:
5(-1m+2)
We multiply parentheses
-5m+10
Back to the equation:
-(-5m+10)
We get rid of parentheses
-4m+5m-10+6=0
We add all the numbers together, and all the variables
m-4=0
We move all terms containing m to the left, all other terms to the right
m=4

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