2(3-2x)=3(x-2)

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Solution for 2(3-2x)=3(x-2) equation: 



2(3-2x)=3(x-2)

We move all terms to the left:

2(3-2x)-(3(x-2))=0

We add all the numbers together, and all the variables

2(-2x+3)-(3(x-2))=0

We multiply parentheses

-4x-(3(x-2))+6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-4x-3x+6+6=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7

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