2(3-2x)=5(4x-1)

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Solution for 2(3-2x)=5(4x-1) equation: 



2(3-2x)=5(4x-1)

We move all terms to the left:

2(3-2x)-(5(4x-1))=0

We add all the numbers together, and all the variables

2(-2x+3)-(5(4x-1))=0

We multiply parentheses

-4x-(5(4x-1))+6=0



We calculate terms in parentheses: -(5(4x-1)), so:

5(4x-1)

We multiply parentheses

20x-5

Back to the equation:

-(20x-5)



We get rid of parentheses

-4x-20x+5+6=0

We add all the numbers together, and all the variables

-24x+11=0

We move all terms containing x to the left, all other terms to the right

-24x=-11

x=-11/-24

x=11/24

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