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2(3-2x)=6x+16
We move all terms to the left:
2(3-2x)-(6x+16)=0
We add all the numbers together, and all the variables
2(-2x+3)-(6x+16)=0
We multiply parentheses
-4x-(6x+16)+6=0
We get rid of parentheses
-4x-6x-16+6=0
We add all the numbers together, and all the variables
-10x-10=0
We move all terms containing x to the left, all other terms to the right
-10x=10
x=10/-10
x=-1
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