2(3-2y)-4y=5-4(y-3)

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Solution for 2(3-2y)-4y=5-4(y-3) equation: 



2(3-2y)-4y=5-4(y-3)

We move all terms to the left:

2(3-2y)-4y-(5-4(y-3))=0

We add all the numbers together, and all the variables

2(-2y+3)-4y-(5-4(y-3))=0

We add all the numbers together, and all the variables

-4y+2(-2y+3)-(5-4(y-3))=0

We multiply parentheses

-4y-4y-(5-4(y-3))+6=0



We calculate terms in parentheses: -(5-4(y-3)), so:

5-4(y-3)

determiningTheFunctionDomain
-4(y-3)+5

We multiply parentheses

-4y+12+5

We add all the numbers together, and all the variables

-4y+17

Back to the equation:

-(-4y+17)



We add all the numbers together, and all the variables

-8y-(-4y+17)+6=0

We get rid of parentheses

-8y+4y-17+6=0

We add all the numbers together, and all the variables

-4y-11=0

We move all terms containing y to the left, all other terms to the right

-4y=11

y=11/-4

y=-2+3/4

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