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2(3-3(x+1))-1=2(-19-x)+2x+19
We move all terms to the left:
2(3-3(x+1))-1-(2(-19-x)+2x+19)=0
We add all the numbers together, and all the variables
2(3-3(x+1))-(2(-1x-19)+2x+19)-1=0
We calculate terms in parentheses: -(2(-1x-19)+2x+19), so:We add all the numbers together, and all the variables
2(-1x-19)+2x+19
We add all the numbers together, and all the variables
2x+2(-1x-19)+19
We multiply parentheses
2x-2x-38+19
We add all the numbers together, and all the variables
-19
Back to the equation:
-(-19)
2(3-3(x+1))+18=0
We move all terms containing x to the left, all other terms to the right
2(3-3(x+1))=-18
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