2(3-3y)=36+4y

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Solution for 2(3-3y)=36+4y equation: 



2(3-3y)=36+4y

We move all terms to the left:

2(3-3y)-(36+4y)=0

We add all the numbers together, and all the variables

2(-3y+3)-(4y+36)=0

We multiply parentheses

-6y-(4y+36)+6=0

We get rid of parentheses

-6y-4y-36+6=0

We add all the numbers together, and all the variables

-10y-30=0

We move all terms containing y to the left, all other terms to the right

-10y=30

y=30/-10

y=-3

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