2(3-a)-(-2)(a-3)=-(-3a-2)

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Solution for 2(3-a)-(-2)(a-3)=-(-3a-2) equation: 



2(3-a)-(-2)(a-3)=-(-3a-2)

We move all terms to the left:

2(3-a)-(-2)(a-3)-(-(-3a-2))=0

We add all the numbers together, and all the variables

2(-1a+3)-(-2)(a-3)-(-(-3a-2))=0

We multiply parentheses

-2a-(-2)(a-3)-(-(-3a-2))+6=0

We multiply parentheses ..

-2a-(-2a+6)-(-(-3a-2))+6=0



We calculate terms in parentheses: -(-(-3a-2)), so:

-(-3a-2)

We get rid of parentheses

3a+2

Back to the equation:

-(3a+2)



We get rid of parentheses

-2a+2a-3a-6-2+6=0

We add all the numbers together, and all the variables

-3a-2=0

We move all terms containing a to the left, all other terms to the right

-3a=2

a=2/-3

a=-2/3

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