2(3-b)=3(b-3)

Solution for 2(3-b)=3(b-3) equation:

Simplifying
2(3 + -1b) = 3(b + -3)
(3 * 2 + -1b * 2) = 3(b + -3)
(6 + -2b) = 3(b + -3)

Reorder the terms:
6 + -2b = 3(-3 + b)
6 + -2b = (-3 * 3 + b * 3)
6 + -2b = (-9 + 3b)

Solving
6 + -2b = -9 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
6 + -2b + -3b = -9 + 3b + -3b

Combine like terms: -2b + -3b = -5b
6 + -5b = -9 + 3b + -3b

Combine like terms: 3b + -3b = 0
6 + -5b = -9 + 0
6 + -5b = -9

Add '-6' to each side of the equation.
6 + -6 + -5b = -9 + -6

Combine like terms: 6 + -6 = 0
0 + -5b = -9 + -6
-5b = -9 + -6

Combine like terms: -9 + -6 = -15
-5b = -15

Divide each side by '-5'.
b = 3

Simplifying
b = 3