2(3-k)=22+2k

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Solution for 2(3-k)=22+2k equation: 



2(3-k)=22+2k

We move all terms to the left:

2(3-k)-(22+2k)=0

We add all the numbers together, and all the variables

2(-1k+3)-(2k+22)=0

We multiply parentheses

-2k-(2k+22)+6=0

We get rid of parentheses

-2k-2k-22+6=0

We add all the numbers together, and all the variables

-4k-16=0

We move all terms containing k to the left, all other terms to the right

-4k=16

k=16/-4

k=-4

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