2(3-x)=(x-4)+11

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Solution for 2(3-x)=(x-4)+11 equation: 



2(3-x)=(x-4)+11

We move all terms to the left:

2(3-x)-((x-4)+11)=0

We add all the numbers together, and all the variables

2(-1x+3)-((x-4)+11)=0

We multiply parentheses

-2x-((x-4)+11)+6=0



We calculate terms in parentheses: -((x-4)+11), so:

(x-4)+11

We get rid of parentheses

x-4+11

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We get rid of parentheses

-2x-x-7+6=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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