2(3-x)=16(x+10

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Solution for 2(3-x)=16(x+10 equation: 



2(3-x)=16(x+10

We move all terms to the left:

2(3-x)-(16(x+10)=0

We add all the numbers together, and all the variables

2(-1x+3)-(16(x+10)=0

We multiply parentheses

-2x-(16(x+10)+6=0

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