2(3-x)=16(x-1+

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Solution for 2(3-x)=16(x-1+ equation:



2(3-x)=16(x-1+
We move all terms to the left:
2(3-x)-(16(x-1+)=0
We add all the numbers together, and all the variables
2(-1x+3)-(16(+x)=0
We multiply parentheses
-2x-(16(+x)+6=0

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