2(3-x)=16(x-1+

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Solution for 2(3-x)=16(x-1+ equation: 



2(3-x)=16(x-1+

We move all terms to the left:

2(3-x)-(16(x-1+)=0

We add all the numbers together, and all the variables

2(-1x+3)-(16(+x)=0

We multiply parentheses

-2x-(16(+x)+6=0

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