2(3-x)=3(x-4)-15

Solution for 2(3-x)=3(x-4)-15 equation:

2(3-x)=3(x-4)-15

We move all terms to the left:

2(3-x)-(3(x-4)-15)=0

We add all the numbers together, and all the variables

2(-1x+3)-(3(x-4)-15)=0

We multiply parentheses

-2x-(3(x-4)-15)+6=0


We calculate terms in parentheses: -(3(x-4)-15), so:

3(x-4)-15

We multiply parentheses

3x-12-15

We add all the numbers together, and all the variables

3x-27

Back to the equation:

-(3x-27)


We get rid of parentheses

-2x-3x+27+6=0

We add all the numbers together, and all the variables

-5x+33=0

We move all terms containing x to the left, all other terms to the right

-5x=-33

x=-33/-5

x=6+3/5