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2(3-x)=x-(3x-4)
We move all terms to the left:
2(3-x)-(x-(3x-4))=0
We add all the numbers together, and all the variables
2(-1x+3)-(x-(3x-4))=0
We multiply parentheses
-2x-(x-(3x-4))+6=0
We calculate terms in parentheses: -(x-(3x-4)), so:We get rid of parentheses
x-(3x-4)
We get rid of parentheses
x-3x+4
We add all the numbers together, and all the variables
-2x+4
Back to the equation:
-(-2x+4)
-2x+2x-4+6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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