2(3-y)+6y=12,y=

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Solution for 2(3-y)+6y=12,y= equation: 



2(3-y)+6y=12.y=

We move all terms to the left:

2(3-y)+6y-(12.y)=0

We add all the numbers together, and all the variables

2(-1y+3)+6y-(+12.y)=0

We add all the numbers together, and all the variables

6y+2(-1y+3)-(+12.y)=0

We multiply parentheses

6y-2y-(+12.y)+6=0

We get rid of parentheses

6y-2y-12.y+6=0

We add all the numbers together, and all the variables

-8y+6=0

We move all terms containing y to the left, all other terms to the right

-8y=-6

y=-6/-8

y=3/4

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