2(3-y)-4(y+2)+20=0

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Solution for 2(3-y)-4(y+2)+20=0 equation:


Simplifying
2(3 + -1y) + -4(y + 2) + 20 = 0
(3 * 2 + -1y * 2) + -4(y + 2) + 20 = 0
(6 + -2y) + -4(y + 2) + 20 = 0

Reorder the terms:
6 + -2y + -4(2 + y) + 20 = 0
6 + -2y + (2 * -4 + y * -4) + 20 = 0
6 + -2y + (-8 + -4y) + 20 = 0

Reorder the terms:
6 + -8 + 20 + -2y + -4y = 0

Combine like terms: 6 + -8 = -2
-2 + 20 + -2y + -4y = 0

Combine like terms: -2 + 20 = 18
18 + -2y + -4y = 0

Combine like terms: -2y + -4y = -6y
18 + -6y = 0

Solving
18 + -6y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + -6y = 0 + -18

Combine like terms: 18 + -18 = 0
0 + -6y = 0 + -18
-6y = 0 + -18

Combine like terms: 0 + -18 = -18
-6y = -18

Divide each side by '-6'.
y = 3

Simplifying
y = 3

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