2(3-y-1)+3(y-4)=13

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Solution for 2(3-y-1)+3(y-4)=13 equation: 


Simplifying
2(3 + -1y + -1) + 3(y + -4) = 13

Reorder the terms:
2(3 + -1 + -1y) + 3(y + -4) = 13

Combine like terms: 3 + -1 = 2
2(2 + -1y) + 3(y + -4) = 13
(2 * 2 + -1y * 2) + 3(y + -4) = 13
(4 + -2y) + 3(y + -4) = 13

Reorder the terms:
4 + -2y + 3(-4 + y) = 13
4 + -2y + (-4 * 3 + y * 3) = 13
4 + -2y + (-12 + 3y) = 13

Reorder the terms:
4 + -12 + -2y + 3y = 13

Combine like terms: 4 + -12 = -8
-8 + -2y + 3y = 13

Combine like terms: -2y + 3y = 1y
-8 + 1y = 13

Solving
-8 + 1y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1y = 13 + 8

Combine like terms: -8 + 8 = 0
0 + 1y = 13 + 8
1y = 13 + 8

Combine like terms: 13 + 8 = 21
1y = 21

Divide each side by '1'.
y = 21

Simplifying
y = 21

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