2(3/2b+1)+2b=28

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Solution for 2(3/2b+1)+2b=28 equation: 



2(3/2b+1)+2b=28

We move all terms to the left:

2(3/2b+1)+2b-(28)=0



Domain of the equation: 2b+1)!=0

b∈R



We add all the numbers together, and all the variables

2b+2(3/2b+1)-28=0

We multiply parentheses

2b+6b+2-28=0

We add all the numbers together, and all the variables

8b-26=0

We move all terms containing b to the left, all other terms to the right

8b=26

b=26/8

b=3+1/4

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